Pretvarjanje niza časovnih žigov Unix v berljiv datum

V Pythonu imam niz, ki predstavlja unixov časovni žig (npr. "1284101485"), in bi ga rad pretvoril v berljiv datum. Ko uporabim time.strftime, dobim napako TypeError:

>>>import time
>>>print time.strftime("%B %d %Y", "1284101485")

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: argument must be 9-item sequence, not str
martineau
Edited question Ndopoldan 51p29.3.20183tni 51trdopoldanni marec 2018 в 12:19
Programiranje
datetime python strftime unix-timestamp
Ndopoldan 58p10.9.20104tni 58trdopoldanni september 2010 в 6:56
17 ogledi

Uporabite modul datetime:

from datetime import datetime
ts = int("1284101485")

# if you encounter a "year is out of range" error the timestamp
# may be in milliseconds, try `ts /= 1000` in that case
print(datetime.utcfromtimestamp(ts).strftime('%Y-%m-%d %H:%M:%S'))
Steven Kryskalla
Edited answer Npopoldan 23p14.8.20181tni 23trpopoldanni avgust 2018 в 6:21
Komentarji (11)
 
>>> from datetime import datetime
>>> datetime.fromtimestamp(1172969203.1)
datetime.datetime(2007, 3, 4, 0, 46, 43, 100000)

Povzeto po http://seehuhn.de/pages/pdate

Komentarji (0)
 
>>> import time
>>> time.ctime(int("1284101485"))
'Fri Sep 10 16:51:25 2010'
>>> time.strftime("%D %H:%M", time.localtime(int("1284101485")))
'09/10/10 16:51'
Komentarji (1)