客户端发送SOAP请求并接收响应

试图创建一个C#客户端（将被开发为Windows服务），向一个Web服务发送SOAP请求（并获得结果）。

从这个问题我看到了这个代码。

protected virtual WebRequest CreateRequest(ISoapMessage soapMessage)
{
    var wr = WebRequest.Create(soapMessage.Uri);
    wr.ContentType = "text/xml;charset=utf-8";
    wr.ContentLength = soapMessage.ContentXml.Length;

    wr.Headers.Add("SOAPAction", soapMessage.SoapAction);
    wr.Credentials = soapMessage.Credentials;
    wr.Method = "POST";
    wr.GetRequestStream().Write(Encoding.UTF8.GetBytes(soapMessage.ContentXml), 0, soapMessage.ContentXml.Length);

    return wr;
}

public interface ISoapMessage
{
    string Uri { get; }
    string ContentXml { get; }
    string SoapAction { get; }
    ICredentials Credentials { get; }
}

看起来不错，有谁知道如何使用它，以及它是否是最佳做法？

JoKeRxbLaCk
已编辑的问题 1日 三月 2019 в 1:50
编程
soap c# webservice-client
25日 一月 2011 в 9:32
15 种观点
解决办法

我通常使用另一种方式来做同样的事情

using System.Xml;
using System.Net;
using System.IO;

public static void CallWebService()
{
    var _url = "http://xxxxxxxxx/Service1.asmx";
    var _action = "http://xxxxxxxx/Service1.asmx?op=HelloWorld";

    XmlDocument soapEnvelopeXml = CreateSoapEnvelope();
    HttpWebRequest webRequest = CreateWebRequest(_url, _action);
    InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest);

    // begin async call to web request.
    IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null);

    // suspend this thread until call is complete. You might want to
    // do something usefull here like update your UI.
    asyncResult.AsyncWaitHandle.WaitOne();

    // get the response from the completed web request.
    string soapResult;
    using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
    {
        using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
        {
            soapResult = rd.ReadToEnd();
        }
        Console.Write(soapResult);        
    }
}

private static HttpWebRequest CreateWebRequest(string url, string action)
{
    HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
    webRequest.Headers.Add("SOAPAction", action);
    webRequest.ContentType = "text/xml;charset=\"utf-8\"";
    webRequest.Accept = "text/xml";
    webRequest.Method = "POST";
    return webRequest;
}

private static XmlDocument CreateSoapEnvelope()
{
    XmlDocument soapEnvelopeDocument = new XmlDocument();
    soapEnvelopeDocument.LoadXml(@"1232");
    return soapEnvelopeDocument;
}

private static void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest)
{
    using (Stream stream = webRequest.GetRequestStream())
    {
        soapEnvelopeXml.Save(stream);
    }
}
Demodave
编辑本段答案5日 六月 2019 в 8:12
评论(14)

我得到了这个简单的解决方案这里。

在.NET 4.0 C#中发送SOAP请求和接收响应，无需使用WSDL或代理类：

class Program
    {
        /// 
        /// Execute a Soap WebService call
        /// 
        public static void Execute()
        {
            HttpWebRequest request = CreateWebRequest();
            XmlDocument soapEnvelopeXml = new XmlDocument();
            soapEnvelopeXml.LoadXml(@"<?xml version=""1.0"" encoding=""utf-8""?>




                ");

            using (Stream stream = request.GetRequestStream())
            {
                soapEnvelopeXml.Save(stream);
            }

            using (WebResponse response = request.GetResponse())
            {
                using (StreamReader rd = new StreamReader(response.GetResponseStream()))
                {
                    string soapResult = rd.ReadToEnd();
                    Console.WriteLine(soapResult);
                }
            }
        }
        /// 
        /// Create a soap webrequest to [Url]
        /// 
        /// 
        public static HttpWebRequest CreateWebRequest()
        {
            HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(@"http://localhost:56405/WebService1.asmx?op=HelloWorld");
            webRequest.Headers.Add(@"SOAP:Action");
            webRequest.ContentType = "text/xml;charset=\"utf-8\"";
            webRequest.Accept = "text/xml";
            webRequest.Method = "POST";
            return webRequest;
        }

        static void Main(string[] args)
        {
            Execute();
        }
    }
评论(5)

最好的做法是引用WSDL并像网络服务参考一样使用它。 这更容易，效果也更好，但如果你没有WSDL，XSD定义也是一段好的代码。

its4zahoor
编辑本段答案5日 二月 2019 в 9:15
评论(6)